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  • hdu 3585 maximum shortest distance(二分+最大团)

    二分距离,求最大团,看是否>=K

    View Code
    #include<iostream>
    #include<algorithm>
    #include<string>
    #include<math.h>
    using namespace std;
    const int N = 50+10;
    int dis[N][N],dd[N*N];
    int dp[N];
    bool inset[N],g[N][N];
    int n,best,ord[N],deg[N];
    bool found;
    inline void Memcpy(bool *d,bool *s)
    {   
        for(int i=0;i<n;i++)   
            d[i]=s[ord[i]];
    }
    bool cmp(int a,int b)
    {  
        return deg[a]<deg[b];
    }
    inline int find(int start,bool *s)
    {   
        for(int i=start+1;i<n;i++)   
            if(s[i])  
                return i; 
        return -1;
    }
    void clique(bool *s,int start,int len)
    {   
        int first=find(start,s),i;  
        if(first==-1) 
        {       
            if(len>best)   
            {    
                best=len;   
                found=true;  
            }    
            return ; 
        }   
        bool tmp[N];
        while(first!=-1) 
        {       
            if(len+n-start<=best || len+dp[first]<=best)  
                return ;      
            tmp[first]=false;   
            for(i=first+1;i<n;i++)    
                tmp[i]=s[i]&g[ord[first]][ord[i]];  
            clique(tmp,first,len+1);   
            if(found) return ;      
            first=find(first,s);  
        }
    }
    inline int get_clique(int dist)
    {
        memset(g,false,sizeof(g));
        memset(deg,0,sizeof(deg));
        memset(dp,0,sizeof(dp));
        for(int i=0;i<n;i++)
        {
            ord[i]=i;
            g[i][i]=true;
            for(int j=i+1;j<n;j++)
            {
                if(dis[i][j]>=dist)
                {
                    g[i][j]=g[j][i]=true;
                    deg[i]++,deg[j]++;
                }
            }
        }
        sort(ord,ord+n,cmp);
        best=0;dp[n-1]=1;
        for(int i=n-2;i>=0;i--)
        {
            Memcpy(inset,g[ord[i]]);
            found=false;
            clique(inset,i,1);
            dp[i]=best;
        }
        return dp[0];
    }
    struct Point
    {
        int x, y;
    }p[N];
    inline int get_dis(Point a,Point b)
    {
        return (a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y);
    }
    int main()
    {
        int k;
        while(scanf("%d %d",&n,&k)==2)
        {
            for(int i=0;i<n;i++)
                scanf("%d %d",&p[i].x,&p[i].y);
            int t=0;
            for(int i=0;i<n;i++)
            {
                for(int j=i+1;j<n;j++)
                {
                    dis[i][j]=dis[j][i]=get_dis(p[i],p[j]);
                    dd[t++]=dis[i][j];
                }
            }
            sort(dd,dd+t);
            int left=0,right=t-1,mid;
            while(left<=right)
            {
                mid=(left+right)>>1;
                if(get_clique(dd[mid])>=k)
                    left=mid+1;
                else right=mid-1;
            }
            printf("%.2f\n",sqrt(double(dd[left-1])));
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/nanke/p/2445214.html
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