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  • codecademy练习记录--Learn Python(70%)

    ##############################################################################
    # codecademy python 5.5
    # Define a function factorial that takes an integer x as input.
    # Calculate and return the factorial of that number.
    # def digit_sum(x):
    # mul = 1
    # for i in range(1,x+1):
    # mul = i*mul
    # print(mul)
    # digit_sum(6)
    ##############################################################################
    # codecademy python 5.6
    # Define a function called is_prime that takes a number x as input.
    # For each number n from 2 to x - 1, test if x is evenly divisible by n.
    # If it is, return False.
    # If none of them are, then return True.
    # def is_prime(x):
    # for i in range(2,x):
    # if x%i ==0:
    # return True
    # else:
    # return False
    # is_prime(100)
    ##############################################################################
    # codecademy python 5.7
    # Define a function called reverse that takes a string textand returns that string in reverse.
    # For example: reverse("abcd") should return "dcba".
    # You may not use reversed or [::-1] to help you with this.
    # You may get a string containing special characters (for example, !, @, or #).
    # def Read(str):
    # return str[::-1]
    # print(Read('abc'))
    ##############################################################################
    # codecademy python 5.8
    # Define a function called anti_vowel that takes one string, text,
    # as input and returns the text with all of the vowels removed.
    # For example: anti_vowel("Hey You!") should return "Hy Y!".
    # Don't count Y as a vowel. Make sure to remove lowercase and uppercase vowels.
    # import re
    # def anti_vowel(str):
    # print(re.sub('[aeiou]','',str))
    # anti_vowel('Hey You!')
    ##############################################################################
    # codecademy python 5.9
    # Define a function scrabble_score that takes a string word as input
    # and returns the equivalent scrabble score for that word.
    # Assume your input is only one word containing no spaces or punctuation.
    # As mentioned, no need to worry about score multipliers!
    # Your function should work even if the letters you get are uppercase, lowercase, or a mix.
    # Assume that you're only given non-empty strings.
    # score = {"a": 1, "c": 3, "b": 3, "e": 1, "d": 2, "g": 2,
    # "f": 4, "i": 1, "h": 4, "k": 5, "j": 8, "m": 3,
    # "l": 1, "o": 1, "n": 1, "q": 10, "p": 3, "s": 1,
    # "r": 1, "u": 1, "t": 1, "w": 4, "v": 4, "y": 4,
    # "x": 8, "z": 10}
    # word = str(input()).lower()
    # def scrabble_score(word):
    # sum = 0
    # for item in word:
    # sum = score[item]+sum
    # print(sum)
    # scrabble_score(word)
    ##############################################################################
    # codecademy python 5.10
    # Write a function called censor that takes two strings, text and word, as input.
    # It should return the text with the word you chose replaced with asterisks. For example:
    # censor("this hack is wack hack", "hack")
    # should return:
    # "this **** is wack ****"
    # Assume your input strings won't contain punctuation or upper case letters.
    # The number of asterisks you put should correspond to the number of letters in the censored word.
    # text = 'this hack is wack hack'
    # word = 'hack'
    # def censor(text,word):
    # num = 0
    # for i in word:
    # num +=1
    # print(text.replace(word,'*'*num))
    # censor(text,word)
    ##############################################################################
    # codecademy python 5.11
    # Define a function called count that has two arguments called sequence and item.
    # Return the number of times the item occurs in the list.
    # For example: count([1, 2, 1, 1], 1) should return 3 (because 1 appears 3 times in the list).
    # There is a list method in Python that you can use for this, but you should do it the long way for practice.
    # Your function should return an integer.
    # The item you input may be an integer, string, float, or even another list!
    # Be careful not to use list as a variable name in your code—it's a reserved word in Python!
    # def count(sequence,item):
    # sum = 0
    # for i in sequence:
    # if i == item:
    # sum+=1
    # return sum
    ##############################################################################
    # codecademy python 5.12
    # Define a function called purify that takes in a list of numbers,
    # removes all odd numbers in the list, and returns the result.
    # For example, purify([1,2,3]) should return [2].
    # Do not directly modify the list you are given as input;
    # instead, return a new list with only the even numbers.
    # def purify(x):
    # li = []
    # for i in x:
    # if i %2 ==0:
    # li.append(i)
    # return li
    # print(purify([1,2,3,4]))
    ##############################################################################
    # codecademy python 5.13
    # Define a function called product that takes a list of integers as input and
    # returns the product of all of the elements in the list.
    # For example: product([4, 5, 5]) should return 100 (because 4 * 5 * 5 is 100).
    # Don't worry about the list being empty.
    # Your function should return an integer.
    # def product(x):
    # mul = 1
    # for i in x:
    # mul = i*mul
    # return mul
    # print(product([12,4,3]))
    ##############################################################################
    # codecademy python 5.14
    # Write a function remove_duplicates that takes in a list and removes elements of the list that are the same.
    # For example: remove_duplicates([1, 1, 2, 2]) should return [1, 2].
    # Don't remove every occurrence, since you need to keep a single occurrence of a number.
    # The order in which you present your output does not matter.
    # So returning [1, 2, 3] is the same as returning [3, 1, 2].
    # Do not modify the list you take as input! Instead, return a new list.
    # def remove_duplicates(li):
    # li1 = []
    # for i in li:
    # if i not in li1:
    # li1.append(i)
    # return li1
    # print(remove_duplicates([1,1,2,2,3,3,4]))
    ##############################################################################
    # codecademy python 5.15
    # Write a function called median that takes a list as an input
    # and returns the median value of the list. For example: median([1, 1, 2]) should return 1.
    # The list can be of any size and the numbers are not guaranteed to be in any particular order. Make sure to sort it!
    # If the list contains an even number of elements, your function should return the average of the middle two.
    # def median(li):
    # li = sorted(list(li))
    # print(li)
    # num = 0
    # for i in li:
    # num +=1
    # if (num-1)%2==0:
    # return li[int(num/2)]
    # else:
    # return ((li[int((num/2-0.5)-1)]+li[int((num/2-0.5)+1)]))/2
    # print(median([6,2,4,8,9,1,2,3,3,7]))
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  • 原文地址:https://www.cnblogs.com/pandaboy1123/p/9055396.html
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