[leetcode] 058. Length of Last Word 解题报告

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 
Given s = "Hello World",
return 5.

注意下非空串的末尾是空字符的情况就行

public int lengthOfLastWord(String s) {
        int result = 0;
        if (s == null || s.length() == 0 || s.split(" ").length == 0) {
            return result;
        }
        if (!s.contains(" ")) {
            return s.length();
        }
        boolean lastChar = false;
        for (int i = s.length() - 1; i >= 0; i--) {
            if (' ' == s.charAt(i) && lastChar) {
                break;
            }
            if (' ' != s.charAt(i)) {
                if (!lastChar) {
                    lastChar = true;
                }
                result += 1;
            }
        }
        return result;
    }