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  • day24,python习题

    今日作业

    有两个列表,分别存放来老男孩报名学习linux和python课程的学生名字
    linux=['钢弹','小壁虎','小虎比','alex','wupeiqi','yuanhao']
    python=['dragon','钢弹','zhejiangF4','小虎比']

    问题一:得出既报名linux又报名python的学生列表
    问题二:得出只报名linux,而没有报名python的学生列表
    问题三:得出只报名python,而没有报名linux的学生列表

    -------------------------------------------------------------------------------------
    #作业1,2,3
    i=[i for i in linux if i in python]
    print(i)

    i=[ i for i in linux if not i in python]
    print(i)

    i=[i for i in python if not i in linux]
    print(i)

    -----------------------------------------------------------------------------------------------
    shares={
    'IBM':36.6,
    'lenovo':27.3,
    'huawei':40.3,
    'oldboy':3.2,
    'ocean':20.1
    }


    问题一:得出股票价格大于30的股票名字列表
    for i in shares:
    if shares[i] > 30:
    print (i)
    ------------------------------------------------------------
    i=[i for i in shares if shares[i] > 30]
    print(i)
    ----------------------------------------------------------------------


    问题二:求出所有股票的总价格
    print((i for i in shares.values()))
    ----------------------------------------------------------------

    作业3

    l=[10,2,3,4,5,6,7]
    得到一个新列表l1,新列表中每个元素是l中对应每个元素值的平方
    过滤出l1中大于40的值,然后求和
    ---------------------------------------------------------------------------------------
    l = [10, 2, 3, 4, 5, 6, 7]
    l1=[ i*i for i in l]
    print( sum( i for i in l1 if i >40 ))

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  • 原文地址:https://www.cnblogs.com/pyyu/p/6701146.html
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