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  • 机器学习之朴素贝叶斯

    首先了解一下三个比较重要的公式:

    条件概率公式:P(A|B)=P(AB)/P(B)

    全概率公式:

    贝叶斯:P(B|A) = P(A|B)P(B)/P(A)

    优 点 :在数据较少的情况下仍然有效,可以处理多类别问题。
    缺 点 :对于输入数据的准备方式较为敏感。
    适用数据类型:标称型数据。


    朴素贝叶斯中朴素二字的含义:假设各个特征之间相互独立。即一个特征或者单词的出现可能性与它和其他单词相邻没有关系。

    朴素贝叶斯中的另外一个假设:每个特征同等重要。

    (尽管上述假设存在一些瑕疵,但是朴素贝叶斯的实际效果却是很好)

     

     使用条件概率进行分类:

    从词向量计算概率:

    完整代码以及数据集地址:

     https://github.com/qwqwqw110/machineLearningInactionCode/tree/master/%E6%9C%B4%E7%B4%A0%E8%B4%9D%E5%8F%B6%E6%96%AF

    朴素贝叶斯分类器的实现:

    import numpy as np
    import re
    import random
    
    # 创建一些实验样本
    def loadDataSet():
        postingList=[['my', 'dog', 'has', 'flea', 'problems', 'help', 'please'],
                     ['maybe', 'not', 'take', 'him', 'to', 'dog', 'park', 'stupid'],
                     ['my', 'dalmation', 'is', 'so', 'cute', 'I', 'love', 'him'],
                     ['stop', 'posting', 'stupid', 'worthless', 'garbage'],
                     ['mr', 'licks', 'ate', 'my', 'steak', 'how', 'to', 'stop', 'him'],
                     ['quit', 'buying', 'worthless', 'dog', 'food', 'stupid']]
        classVec = [0,1,0,1,0,1]    #1 is abusive, 0 not
        return postingList,classVec
    
    
    # 创建词典
    def createVocabList(dataSet):
        vocabSet = set([])
        for document in dataSet:
            vocabSet = vocabSet | set(document)
        return vocabSet
    
    
    # 输出文档向量,vocabList中的单词同时在inputSet中存在为1,否则为0
    
    # 词集模型,即将每个词出现与否作为一个特征,出现多次和出现一次效果相同
    def setOfWords2Vec(vocabList, inputSet):
        returnVec = [0]*len(vocabList)
        for word in inputSet:
            if word in vocabList:
                returnVec[list(vocabList).index(word)] = 1
            else: print("the word: %s is not in my Vocabulary!" % word)
        return returnVec
    
    
    #词袋模型,即将每个词出现次数作为特征值,出现一次和出现多次效果不同
    def bagOfWords2Vec(vocabList, inputSet):
        returnVec = [0]*len(vocabList)
        for word in inputSet:
            if word in vocabList:
                returnVec[list(vocabList).index(word)] += 1
            else: print("the word: %s is not in my Vocabulary!" % word)
        return returnVec
    
    
    # 训练样本
    def trainNB0(trainMatrix, trainCategory):
        numTrainDocs = len(trainMatrix)
        numWords = len(trainMatrix[0])
        pAbusive = sum(trainCategory) / float(numTrainDocs)
        ''' 
        利用贝叶斯进行分类时,需要计算多个概率的乘积,若有概率为0,则最后乘积也为0
        为了降低这种情况的发生,将每个文档中每个单词出现的次数初始化为1
        并且将分母初始化为2
        '''
        p0Denom = np.ones(numWords)
        p1Denom = np.ones(numWords)
        p0Sum = 2.0
        p1Sum = 2.0
        
        for i in range(numTrainDocs):
            if trainCategory[i] == 1:
                p1Denom += trainMatrix[i]
                p1Sum += sum(trainMatrix[i])
            else:
                p0Denom += trainMatrix[i]
                p0Sum += sum(trainMatrix[i])
        # 概率向量的每个元素都很小,后边需要这些元素相乘,所以为了防止向下溢出,对此处概率取对数
        p0Denom = np.log(p0Denom / p0Sum)
        p1Denom = np.log(p1Denom / p1Sum)
        
        return p0Denom, p1Denom, pAbusive
    
    
    def classifyNB(vec2Classify, p0Vec, p1Vec, pClass1):
        p1 = sum(p1Vec * vec2Classify) + np.log(pClass1)
        p0 = sum(p0Vec * vec2Classify) + np.log(1 - pClass1)
        if p1 > p0:
            return 1
        else:
            return 0
    
    # just for test
    def testNB():
        listOposts, listClasses = loadDataSet()
        myVocabList = createVocabList(listOposts)
        trainMatrix = []
        for postinDoc in listOposts:
            trainMatrix.append(setOfWords2Vec(myVocabList, postinDoc))
        p0, p1, pAbusive = trainNB0(trainMatrix, listClasses)
        
        testDoc = ['my', 'food']
        testVec = np.array(setOfWords2Vec(myVocabList, testDoc))
        print(testDoc, "the class is:%d" % classifyNB(testVec, p0, p1, pAbusive))
    
    
    # 将文本转化为所需要的格式
    def textParse(bigString):
        # !!!注意此处,书中代码有错误,将 re.split(r'W*', bigString) 改为 re.split(r'W+', bigString)
        listOfTokens = re.split(r'W+', bigString) # 利用正则表达式,只读取字母和数字
        ret = [tok.lower() for tok in listOfTokens if len(tok) > 2] # 返回长度大于2的单词的小写形式
        return ret
    
    # 利用垃圾邮件分类对朴素贝叶斯进行测试
    def spamTest():
        docList = []; fullTest = []; classList = []
        for i in range(1, 26): #读取文件
            fr = open('email/spam/%d.txt' % i)
            doc = fr.read()
            wordList = textParse(doc) # 读取垃圾邮件并转化为我们所需要的格式
            docList.append(wordList)
            fullTest.extend(wordList)
            classList.append(1)
            
            wordList = textParse(open('email/ham/%d.txt' % i).read()) # 读取非垃圾邮件并转化为我们所需要的格式
            docList.append(wordList)
            fullTest.extend(wordList)
            classList.append(0)
    
        vocabList = createVocabList(docList) # 创建词典
        trainingSet = list(range(50))
        testSet = []
        for i in range(10):
            randIndex = int(random.uniform(0, len(trainingSet)))
            testSet.append(trainingSet[randIndex])
            del(trainingSet[randIndex])
            
        trainMat = []; trainClasses = []
        for docIndex in trainingSet:
            trainMat.append(setOfWords2Vec(vocabList, docList[docIndex]))
            trainClasses.append(classList[docIndex])
            
        p0V, p1V, pSpam = trainNB0(trainMat, trainClasses)
        errorCount = 0
        for docIndex in testSet:
            testVec = setOfWords2Vec(vocabList, docList[docIndex])
            if classifyNB(np.array(testVec), p0V, p1V, pSpam) != classList[docIndex]:
                errorCount += 1
        rate = float(errorCount) / float(len(testSet))
        #print("the error rate is: ", rate)
        return rate
    
    s = 0.0
    for i in range(10):
        s += spamTest()
    print('total rate:', s / 10.0)
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  • 原文地址:https://www.cnblogs.com/qiang-wei/p/10756271.html
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