zoukankan      html  css  js  c++  java
  • bzoj1014: [JSOI2008]火星人prefix

    欸 这不是做过的原题吗qwq

    顺手码一码

    欸怎么各种不对啊

    哦 以前基本没用过get_segment 基本都是split的

    嗯 就是这个东西 要开个tmp保存一下结果 不然会出奇奇怪股的事情

      1 #include<cstdio>
      2 #include<cstring>
      3 #include<cstdlib>
      4 #include<algorithm>
      5 #include<iostream>
      6 
      7 using namespace std;
      8 
      9 void setIO(const string& s) {
     10     freopen((s + ".in").c_str(), "r", stdin);
     11     freopen((s + ".out").c_str(), "w", stdout);
     12 }
     13 template<typename Q> Q read(Q& x) {
     14     static char c, f;
     15     for(f = 0; c = getchar(), !isdigit(c); ) if(c == '-') f = 1;
     16     for(x = 0; isdigit(c); c = getchar()) x = x * 10 + c - '0';
     17     if(f) x = -x;
     18     return x;
     19 }
     20 template<typename Q> Q read() {
     21     static Q x; read(x); return x;
     22 }
     23 
     24 typedef unsigned uLL;
     25 const int N = 150000 + 10;
     26 
     27 uLL powers[N];
     28 
     29 struct Node *null, *pis;
     30 struct Node {
     31     int v, sz;
     32     uLL h;
     33     Node *ch[2];
     34     
     35     Node(int v = 0) : v(v) {
     36         h = v;
     37         sz = 1;
     38         ch[0] = ch[1] = null;
     39     }
     40     
     41     int size() const {
     42         return this ? sz : 0;
     43     }
     44     
     45     void maintain() {
     46         sz = ch[0]->sz + ch[1]->sz + 1;
     47         h = ch[0]->h * powers[ch[1]->sz + 1] + (uLL) v * powers[ch[1]->sz] + ch[1]->h;
     48     }
     49     
     50     int cmp(int k) const {
     51         int s = ch[0]->sz + 1;
     52         if(s == k) return -1;
     53         return k < s ? 0 : 1;
     54     }
     55     
     56     void *operator new(size_t) {
     57         return pis++;
     58     }
     59 }pool[N], *root;
     60 
     61 void rotate(Node *&o, int d) {
     62     Node *t = o->ch[d];
     63     o->ch[d] = t->ch[d ^ 1];
     64     t->ch[d ^ 1] = o;
     65     o->maintain();
     66     (o = t)->maintain();
     67 }
     68 
     69 void splay(Node *&o, int k) {
     70     int d = o->cmp(k);
     71     if(d == -1) return;
     72     if(d == 1) k -= o->ch[0]->sz + 1;
     73     Node *&c = o->ch[d];
     74     int d2 = c->cmp(k);
     75     if(d2 != -1) {
     76         if(d2 == 1) k -= c->ch[0]->sz + 1;
     77         splay(c->ch[d2], k);
     78         if(d == d2) rotate(o, d);
     79         else rotate(c, d2);
     80     }
     81     rotate(o, d);
     82 }
     83 
     84 void split(Node *o, int k, Node *&l, Node *&r) {
     85     splay(o, k);
     86     l = o;
     87     r = o->ch[1];
     88     o->ch[1] = null;
     89     o->maintain();
     90 }
     91 
     92 Node *merge(Node *l, Node *r) {
     93     splay(l, l->sz);
     94     l->ch[1] = r;
     95     return l->maintain(), l;
     96 }
     97 
     98 char s[N];
     99 
    100 void build(Node*& o, int l, int r) {
    101     if(l > r) return o = null, void();
    102     int mid = (l + r) >> 1;
    103     o = new Node(s[mid]);
    104     build(o->ch[0], l, mid - 1);
    105     build(o->ch[1], mid + 1, r);
    106     o->maintain();
    107 }
    108 
    109 void splay_init() {
    110     pis = pool;
    111     null = new Node(0);
    112     null->ch[0] = null->ch[1] = null;
    113     null->sz = 0;
    114 }
    115 
    116 Node *segment(int l, int r) {
    117     splay(root, l);
    118     splay(root->ch[1], r + 1);
    119     return root->ch[1]->ch[0];
    120 }
    121 
    122 void update() {
    123     root->ch[1]->ch[0]->maintain();
    124     root->ch[1]->maintain();
    125     root->maintain();
    126 }
    127 
    128 void print(Node *o) {
    129     if(o == null) return;
    130     print(o->ch[0]);
    131     fprintf(stderr, "%c", (char)o->v);
    132     print(o->ch[1]);
    133 }
    134 
    135 const uLL xx[] = {53, 1313, 1003};
    136 
    137 int main() {
    138 #ifdef DEBUG
    139     freopen("in.txt", "r", stdin);
    140     freopen("out.txt", "w", stdout);
    141 #endif
    142     
    143     powers[0] = 1;
    144     for(int j = 1; j < N; j++) powers[j] = powers[j-1] * 1313;
    145     
    146     scanf("%s", s + 1);
    147     int n = strlen(s + 1);
    148     
    149     splay_init();
    150     build(root, 0, n + 1);
    151     
    152 //    print(root);
    153     
    154     char opt[10];
    155     int m, x, y;
    156     scanf("%d", &m);
    157     while(m--) {
    158         scanf("%s%d", opt, &x);
    159         if(opt[0] == 'Q') {
    160             scanf("%d", &y);
    161             int L = 1, R = n - max(x, y) + 1, res = 0;
    162             while(L <= R) {
    163                 int mid = (L + R) >> 1;
    164                 static uLL tmp;
    165                 tmp = segment(x, mid)->h;
    166                 if(tmp == segment(y, mid)->h)
    167                     res = mid, L = mid + 1; else R = mid - 1;
    168             }
    169             printf("%d
    ", res);
    170         }else if(opt[0] == 'R') {
    171             scanf("%s", opt);
    172             segment(x, 1)->v = opt[0];
    173             update();
    174 //            print(root);
    175         }else {
    176             scanf("%s", opt);
    177             static Node *lft, *rgt;
    178             split(root, x + 1, lft, rgt);
    179             root = merge(merge(lft, new Node(opt[0])), rgt);
    180             n++;
    181         }
    182     }
    183     
    184     return 0;
    185 }
    View Code
  • 相关阅读:
    Android:Service通知Activity更新界面
    greendao 查询之数据去重
    Android GreenDao 深查询 n:m 的关系
    java 获取当天(今日)零点零分零秒
    Android Theme.Dialog 到光 AppCompatDialog
    Android 如何利用Activity的Dialog风格完成弹出框设计
    上周热点回顾(9.14-9.20)团队
    .NET跨平台之旅:将示例站点从ASP.NET 5 Beta5升级至Beta7团队
    上周热点回顾(9.7-9.13)团队
    上周热点回顾(8.31-9.6)团队
  • 原文地址:https://www.cnblogs.com/showson/p/5109238.html
Copyright © 2011-2022 走看看