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  • Oracle查询结果中:一列中相同的值或一列中重复的值,只显示一次

    http://www.itpub.net/thread-1768915-1-1.html

    问题:

    CREATE TABLE test(
    ob_id VARCHAR(32),
    ob_name VARCHAR(32)
    );

    INSERT INTO test VALUES('A001','A001-a');
    INSERT INTO test VALUES('A001','A001-b');
    INSERT INTO test VALUES('A001','A001-c');
    INSERT INTO test VALUES('A001','A001-d');
    INSERT INTO test VALUES('A002','A002-a');
    INSERT INTO test VALUES('A002','A002-b');
    INSERT INTO test VALUES('A002','A002-c');
    INSERT INTO test VALUES('A002','A002-d');
    COMMIT;

    select * from test;查询结果:

    OB_ID OB_NAME
    A001 A001-a
    A001 A001-b
    A001 A001-c
    A001 A001-d
    A002 A002-a
    A002 A002-b
    A002 A002-c
    A002 A002-d


    如何实现下面的查询结果?:

    OB_ID OB_NAME
    A001 A001-a
      A001-b
      A001-c
      A001-d
    A002 A002-a
      A002-b
      A002-c
      A002-d

    实现sql:

    --select row_number() over(partition by ob_id order by ob_name) from test;

    --row_number方法
    select decode(row_number() over(partition by ob_id order by ob_name),
    1,
    ob_id) ob_id,
    ob_name
    from test t;

    --lag或lead方法
    select decode(lag(ob_id) over(partition by ob_id order by ob_name),
    ob_id,
    null,
    ob_id) ob_id,
    ob_name
    from test t;

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  • 原文地址:https://www.cnblogs.com/svennee/p/4173346.html
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