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  • [Leetcode] Binary Tree Paths

    Given a binary tree, return all root-to-leaf paths.

    For example, given the following binary tree:

       1
     /   
    2     3
     
      5
    

    All root-to-leaf paths are:

    ["1->2->5", "1->3"]

    分析:深度优先搜索
    /**
     * Definition for a binary tree node.
     * struct TreeNode {
     *     int val;
     *     TreeNode *left;
     *     TreeNode *right;
     *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
     * };
     */
    class Solution {
    public:
        vector<string> result;
        
        vector<string> binaryTreePaths(TreeNode* root) {
            if (root == NULL) return result;
            
            string s;
            binaryTreePaths(root, s+to_string(root->val));
            return result;
        }
        
        void binaryTreePaths(TreeNode* root, string path) {
            if (root->left == NULL && root->right == NULL) {
                result.push_back(path);
                return;
            } else {
                if (root->left != NULL)
                    binaryTreePaths(root->left, path+"->"+to_string(root->left->val));
                
                if (root->right != NULL)
                    binaryTreePaths(root->right, path+"->"+to_string(root->right->val));
            }
    
        }
    };
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  • 原文地址:https://www.cnblogs.com/vincently/p/4771159.html
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