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  • HDU1465+递推

    经典的信封装信问题

    f[ n ]  = ( n-1 ) * ( f[ n-1 ]+f[ n-2 ] )

     1 #include<stdio.h>
     2 #include<string.h>
     3 #include<stdlib.h>
     4 typedef long long int64;
     5 const int maxn = 22;
     6 int64 a[ maxn ];
     7 
     8 void init(){
     9     a[ 0 ] = a[ 1 ] = 0;
    10     a[ 2 ] = 1;
    11     for( int i=3;i<=20;i++ ){
    12         a[ i ] = ( i-1 )*(a[ i-2 ] + a[ i-1 ]);
    13     }
    14     return ;
    15 }
    16 
    17 int main(){
    18     init();
    19     int n;
    20     while( scanf("%d",&n)==1 ){
    21         printf("%I64d
    ",a[ n ]);
    22     }
    23     return 0;
    24 }
    View Code
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  • 原文地址:https://www.cnblogs.com/xxx0624/p/3442262.html
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