DataTable 转 JSON,XML转JSON

 今天总结一下关于DataTable,XML转JSON的方法：

首先需要引入命名空间： using Newtonsoft.Json 1 public string DataTableToJsonWithStringBuilder(DataTable table)

    {
        var jsonString = new StringBuilder();
        if (table.Rows.Count > 0)
        {
              jsonString.Append("[");
            for (int i = 0; i < table.Rows.Count; i++)
            {
                jsonString.Append("{");
                for (int j = 0; j < table.Columns.Count; j++)
                {
                    if (j < table.Columns.Count - 1)
                    {
                        jsonString.Append(""" + table.Columns[j].ColumnName.ToString()
                     + "":" + """
                     + table.Rows[i][j].ToString() + "",");
                    }
                    else if (j == table.Columns.Count - 1)
                    {
                        jsonString.Append(""" + table.Columns[j].ColumnName.ToString()
                     + "":" + """
                     + table.Rows[i][j].ToString() + """);
                    }
                }
                if (i == table.Rows.Count - 1)
                {
                    jsonString.Append("}");
                }
                else
                {
                    jsonString.Append("},");
                }
            }
              jsonString.Append("]");
        }
        return jsonString.ToString();
    }

调用：

var xmlToJson = DataTableToJsonWithStringBuilder(newdt);// datatable转json数组

//XML转JSON

var xmlToJson1 = JsonConvert.SerializeXmlNode(child, Newtonsoft.Json.Formatting.None, true);