zoukankan      html  css  js  c++  java
  • sdut 2413:n a^o7 !(第三届山东省省赛原题,水题,字符串处理)

    n a^o7 !

    Time Limit: 1000MS Memory limit: 65536K

    题目描述

     

    All brave and intelligent fighters, next you will step into a distinctive battleground which is full of sweet and happiness. If you want to win the battle, you must do warm-up according to my instructions, which can make you in the best state preparing to fight. Now please relax yourself and enjoy the good moment. Before you raise your sharp sword to the enemy who guards the battleground, please allow me to tell you a true and romantic story about a samurai like you. 
    Samurai hh fell in love with girl ss, who is charming and demure. He realized the truth that he must spend his remaining life with ss, and resolved to pursue the hard-won affection. One day hh wrote a letter to ss, when she opens the letter with excitement her mind was in tangle. She found herself completely not to figure out the meaning about the letter, which said that "n 55!w ! pue n a^o7 ! n paau !". ss also immersed herself in guessing the meaning of that letter for a long time because of her adore to hh. Finally she called hh to ask the meaning of the letter. On the other side of the phone, hh was too nervous to say. Gradually he calmed down himself and told ss to reverse the letter and read it. Then on both ends of the phone comes the voice at the same time "i need u i love u and i miss u".
    ss wants to tell each of you however you are Brave And Skilled, you shouldn't forget to express your loyal love and romantic feelings to your prince or princess.
    Now the horn sounds for battle,do it by the following input and output. I think each of you will get an "Accepted" in this battle with pleasant mood.

    输入

    Input contains an integer T in the first line, and then T lines follow .Each line contains a message (only contain 'n5!wpuea^o7!' and 
    ' '(space)), the message's length is no more than 100.

    输出

    Output the case number and the message. (As shown in the sample output)

     

    示例输入

    2
    n 55!w ! pue n a^o7 ! n paau !
    n5!wpuea^o7
    

    示例输出

    Case 1: i need u i love u and i miss u
    Case 2: loveandmisu
    

    提示

     

    来源

     2012年"浪潮杯"山东省第三届ACM大学生程序设计竞赛
     
      水题
      因为只会出现“n5!wpuea^o7!”这些字符,所以依次单独处理即可。
      代码:
     1 #include <iostream>
     2 #include <stdio.h>
     3 #include <string.h>
     4 using namespace std;
     5 void work(char a[])
     6 {
     7     int i;
     8     for(i=0;a[i];i++){
     9         switch(a[i]){
    10         case 'n':a[i]='u';break;
    11         case '5':a[i]='s';break;
    12         case 'w':a[i]='m';break;
    13         case 'p':a[i]='d';break;
    14         case 'u':a[i]='n';break;
    15         case 'e':a[i]='a';break;
    16         case 'a':a[i]='e';break;
    17         case '^':a[i]='v';break;
    18         case 'o':a[i]='o';break;
    19         case '7':a[i]='l';break;
    20         case '!':a[i]='i';break;
    21         default:break;
    22         }
    23     }
    24 }
    25 int main()
    26 {
    27     int n,cnt = 1;
    28     cin>>n;
    29     getchar();
    30     while(n--){
    31         char a[110];
    32         cin.getline(a,120,'
    ');
    33         work(a);
    34         cout<<"Case "<<cnt++<<": ";
    35         int len = strlen(a)-1;
    36         for(;len>=0;len--)
    37             cout<<a[len];
    38         cout<<endl;
    39     }
    40     return 0;
    41 }
    42 
    43 
    44 /**************************************
    45     Problem id    : SDUT OJ D 
    46     User name    : Miracle 
    47     Result        : Accepted 
    48     Take Memory    : 472K 
    49     Take Time    : 0MS 
    50     Submit Time    : 2014-04-27 09:16:04  
    51 **************************************/

    Freecode : www.cnblogs.com/yym2013

  • 相关阅读:
    组合数据类型练习
    实验四、递归下降语法分析实验
    词法分析实验报告
    Python基础综合练习
    大数据概述
    一个词法分析程序
    linux基本命令
    有限自动机的构造与识别
    我对编译原理的小小了解
    Scrum 冲刺博客 2
  • 原文地址:https://www.cnblogs.com/yym2013/p/3694738.html
Copyright © 2011-2022 走看看