zoukankan      html  css  js  c++  java
  • 1022 Digital Library

    A Digital Library contains millions of books, stored according to their titles, authors, key words of their abstracts, publishers, and published years. Each book is assigned an unique 7-digit number as its ID. Given any query from a reader, you are supposed to output the resulting books, sorted in increasing order of their ID's.

    Input Specification:

    Each input file contains one test case. For each case, the first line contains a positive integer N (≤) which is the total number of books. Then N blocks follow, each contains the information of a book in 6 lines:

    • Line #1: the 7-digit ID number;
    • Line #2: the book title -- a string of no more than 80 characters;
    • Line #3: the author -- a string of no more than 80 characters;
    • Line #4: the key words -- each word is a string of no more than 10 characters without any white space, and the keywords are separated by exactly one space;
    • Line #5: the publisher -- a string of no more than 80 characters;
    • Line #6: the published year -- a 4-digit number which is in the range [1000, 3000].

    It is assumed that each book belongs to one author only, and contains no more than 5 key words; there are no more than 1000 distinct key words in total; and there are no more than 1000 distinct publishers.

    After the book information, there is a line containing a positive integer M (≤) which is the number of user's search queries. Then M lines follow, each in one of the formats shown below:

    • 1: a book title
    • 2: name of an author
    • 3: a key word
    • 4: name of a publisher
    • 5: a 4-digit number representing the year

    Output Specification:

    For each query, first print the original query in a line, then output the resulting book ID's in increasing order, each occupying a line. If no book is found, print Not Found instead.

    Sample Input:

    3
    1111111
    The Testing Book
    Yue Chen
    test code debug sort keywords
    ZUCS Print
    2011
    3333333
    Another Testing Book
    Yue Chen
    test code sort keywords
    ZUCS Print2
    2012
    2222222
    The Testing Book
    CYLL
    keywords debug book
    ZUCS Print2
    2011
    6
    1: The Testing Book
    2: Yue Chen
    3: keywords
    4: ZUCS Print
    5: 2011
    3: blablabla
    

    Sample Output1: The Testing Book1111111

    2222222
    2: Yue Chen
    1111111
    3333333
    3: keywords
    1111111
    2222222
    3333333
    4: ZUCS Print
    1111111
    5: 2011
    1111111
    2222222
    3: blablabla
    Not Found

    收获:
      1、set是一个有序容器,既能避免排序,又可以避免重复id
      2、cin输入后面使用getline()一定要加getchar()
      3、如果id使用的是int类型,输出的时候一定是这样printf("%07d",id)因为有可能id是这样0000001,这样的话输出是1而不是7位
      本题有两个测试点就是这样
    #include<iostream>
    #include<map>
    #include<set>
    #include<vector>
    using namespace std;
    
    int main()
    {
        int n;
        int id;
        string title,author,keywords,publisher,year;
        map<string,set<int>> query[6];
        cin>>n;
        for(int i=0; i<n; i++)
        {
            cin>>id;
            getchar();
            getline(cin,title);
            query[1][title].insert(id);
            getline(cin,author);
            query[2][author].insert(id);
            while(cin.peek()!='
    ')
            {
                cin>>keywords;
                query[3][keywords].insert(id);
            }
            getchar();
            getline(cin,publisher);
            query[4][publisher].insert(id);
            getline(cin,year);
            query[5][year].insert(id);
        }
        int m;
        cin>>m;
        for(int i=0; i<m; i++)
        {
            int index;
            cin>>index;
            getchar();//"去掉:"
            getchar();//“去掉空格”
            string key;
            getline(cin,key);
            cout<<index<<": "<<key<<endl;
            if(query[index].find(key)!=query[index].end())
            {
                for(auto num:query[index][key])
                    printf("%07d
    ", num);
            }
            else
                cout<<"Not Found"<<endl;
        }
        return 0;
    }
    

      

     
  • 相关阅读:
    WPF之Binding基础八 使用Linq数据作为Binding的源
    WPF之Binding基础七 使用XML数据作为Binding的源
    WPF之Binding基础六 使用ADO.NET作为Binding的数据源
    WPF之Binding基础五 使用集合对象作为列表控件的ItemSource
    WPF之Binding基础四 使用DataContext作为Binding的源
    解决 VS的IISExpress localhost可以访问,127.0.0.1和本机ip访问不了(错误400)
    c# 使用特性封装提供额外行为Validate验证
    c# 反射调用方法、获取设置值、好处和局限性
    c# 反射加读取类、方法、特性、破坏单例
    linq to object使用
  • 原文地址:https://www.cnblogs.com/zhanghaijie/p/10294421.html
Copyright © 2011-2022 走看看