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  • 根据年得到所有星期日的日期

    Go
    --创建函数
    create function GetWeekDays(@year int)
    returns @t table (星期天varchar(20))
    as
    begin
        insert @t
        select  substring(convert(varchar,dateadd(day,x,col),120),1,10) from
        ( select cast(cast(@year as varchar(4))+'-1-1' as datetime) as col )a cross join
        ( select  top 365 b8.i+b7.i + b6.i + b5.i + b4.i +b3.i +b2.i + b1.i + b0.i x
        from(select 0 i union all select 1) b0
        cross join(select 0 i union all select 2) b1
        cross join(select 0 i union all select 4) b2
        cross join(select 0 i union all select 8) b3
        cross join(select 0 i union all select 16) b4
        cross join(select 0 i union all select 32) b5
        cross join(select 0 i union all select 64) b6
        cross join(select 0 i union all select 128) b7
        cross join(select 0 i union all select 256) b8
        order by 1 )b where datepart(dw,dateadd(day,x,col))=1
        return
    end
     
    --测试示例
    select * from dbo.GetWeekDays(2011)
     
    --运行结果
    /*
    星期天
    --------------------
    2011-01-02
    2011-01-09
    2011-01-16
    2011-01-23
    2011-01-30
    2011-02-06
    2011-02-13
    2011-02-20
    2011-02-27
    2011-03-06
    2011-03-13
    2011-03-20
    2011-03-27
    2011-04-03
    2011-04-10
    2011-04-17
    2011-04-24
    2011-05-01
    2011-05-08
    2011-05-15
    2011-05-22
    2011-05-29
    2011-06-05
    2011-06-12
    2011-06-19
    2011-06-26
    2011-07-03
    2011-07-10
    2011-07-17
    2011-07-24
    2011-07-31
    2011-08-07
    2011-08-14
    2011-08-21
    2011-08-28
    2011-09-04
    2011-09-11
    2011-09-18
    2011-09-25
    2011-10-02
    2011-10-09
    2011-10-16
    2011-10-23
    2011-10-30
    2011-11-06
    2011-11-13
    2011-11-20
    2011-11-27
    2011-12-04
    2011-12-11
    2011-12-18
    2011-12-25
     
    (52 row(s) affected)
    */
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  • 原文地址:https://www.cnblogs.com/accumulater/p/6244714.html
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