The Famous Clock

题目484
The Famous Clock
时间限制：1000 ms | 内存限制：65535 KB
难度：1
描述
Mr. B, Mr. G and Mr. M are now in Warsaw, Poland, for the 2012’s ACM-ICPC World Finals Contest.
They’ve decided to take a 5 hours training every day before the contest. Also, they plan to start
training at 10:00 each day since the World Final Contest will do so. The scenery in Warsaw is so
attractive that Mr. B would always like to take a walk outside for a while after breakfast. However,
Mr. B have to go back before training starts, otherwise his teammates will be annoyed. Here is a
problem: Mr. B does not have a watch. In order to know the exact time, he has bought a new watch
in Warsaw, but all the numbers on that watch are represented in Roman Numerals. Mr. B cannot
understand such kind of numbers. Can you translate for him?

输入
Each test case contains a single line indicating a Roman Numerals that to be translated. All the numbers can be found on clocks. That is, each number in the input represents an integer between 1 and 12. Roman Numerals are expressed by strings consisting of uppercase ‘I’, ‘V’ and ‘X’. See the sample input for further information.
输出
For each test case, display a single line containing a decimal number corresponding to the given Roman Numerals.
样例输入
I
II
III
IV
V
VI
VII
VIII
IX
X
XI
XII
样例输出
Case 1: 1
Case 2: 2
Case 3: 3
Case 4: 4
Case 5: 5
Case 6: 6
Case 7: 7
Case 8: 8
Case 9: 9
Case 10: 10
Case 11: 11
Case 12: 12

#include<stdio.h>
#include<string.h>
  int main(){
      char a[5];
      int n=0;
           while(scanf("%s",a)!=EOF){   //有多组数据  没有指定个数  就要EOF
           printf("Case %d: ",++n);  //字符串读取  不用取地址  数组名就是地址    
          if(strcmp(a,"I")==0)
                 printf("1");
            else if(strcmp(a,"II")==0)
                printf("2");
            else if(strcmp(a,"III")==0)
                printf("3");
            else if(strcmp(a,"IV")==0)
                printf("4");
            else if(strcmp(a,"V")==0)
                printf("5");
            else if(strcmp(a,"VI")==0)
              printf("6");
          else if(strcmp(a,"VII")==0)
              printf("7");
          else if(strcmp(a,"VIII")==0)
              printf("8"); 
          else if(strcmp(a,"IX")==0)
              printf("9");
          else if(strcmp(a,"X")==0)
              printf("10");
          else if(strcmp(a,"XI")==0)    
              printf("11");
          else if(strcmp(a,"XII")==0)
             printf("12"); 
           printf("
");  
           }
            return 0;
  }