ACM HDU 1021Fibonacci Again

Fibonacci Again

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 15017    Accepted Submission(s): 7022

Problem Description

There are another kind of Fibonacci numbers: F(0) = 7, F(1) = 11, F(n) = F(n-1) + F(n-2) (n>=2).

 

Input

Input consists of a sequence of lines, each containing an integer n. (n < 1,000,000).

 

Output

Print the word "yes" if 3 divide evenly into F(n).

Print the word "no" if not.

 

Sample Input

0 1 2 3 4 5

 

Sample Output

no no yes no no no

 

Author

Leojay

 

Recommend

JGShining

 

 

找规律：

 

#include<iostream>
using namespace std;
int main()
{
    int n;
    while(cin>>n)
    {
        if(n%4==2)cout<<"yes"<<endl;
        else cout<<"no"<<endl;
    }    
    return 0;
}