zoukankan      html  css  js  c++  java
  • Queue-621. Task Scheduler

    Given a char array representing tasks CPU need to do. It contains capital letters A to Z where different letters represent different tasks.Tasks could be done without original order. Each task could be done in one interval. For each interval, CPU could finish one task or just be idle.

    However, there is a non-negative cooling interval n that means between two same tasks, there must be at least n intervals that CPU are doing different tasks or just be idle. 

    You need to return the least number of intervals the CPU will take to finish all the given tasks.

    Example 1:

    Input: tasks = ["A","A","A","B","B","B"], n = 2
    Output: 8
    Explanation: A -> B -> idle -> A -> B -> idle -> A -> B.
    

    Note:

    1. The number of tasks is in the range [1, 10000].
    2. The integer n is in the range [0, 100].
    class Solution {
    public:
        int leastInterval(vector<char>& tasks, int n) {
            vector<int> cnt(26, 0);
            for (char task : tasks) {
                ++cnt[task - 'A'];
            }
            sort(cnt.begin(), cnt.end());
            int i = 25, mx = cnt[25], len = tasks.size();
            while (i >= 0 && cnt[i] == mx) --i;
            return max(len, (mx - 1) * (n + 1) + 25 - i);
        }
    };
  • 相关阅读:
    高精度加法
    高精度计算(一)
    算法总结
    崛起之路
    2015浙江高考满分作文汇总(9篇)
    努力
    NOIP2015总结
    P3197 [HNOI2008]越狱[组合数学]
    【原创】SPFA判负环
    P1351 联合权值[鬼畜解法]
  • 原文地址:https://www.cnblogs.com/msymm/p/8278252.html
Copyright © 2011-2022 走看看