pandas iloc函数

import pandas as pd
import numpy as np
import matplotlib.pyplot as plt


# 设置输出结果列对齐
pd.set_option('display.unicode.ambiguous_as_wide',True)
pd.set_option('display.unicode.east_asian_width',True)

In [100]:

mydict = [{'a': 1, 'b': 2, 'c': 3, 'd': 4},
          {'a': 100, 'b': 200, 'c': 300, 'd': 400},
          {'a': 1000, 'b': 2000, 'c': 3000, 'd': 4000 },
          {'a': 10000, 'b': 20000, 'c': 30000, 'd': 40000 },
          {'a': 100000, 'b': 200000, 'c': 300000, 'd': 400000 }]
df = pd.DataFrame(mydict)
# 插入一个列-学号
# student_ID = pd.Series([101,102,103,104,105],name = 'ID')
# df.insert(0,column='ID',value = student_ID)
# df.set_index(['ID'],inplace = True)
# print(df.columns)
df

Out[100]:

	a	b	c	d
0	1	2	3	4
1	100	200	300	400
2	1000	2000	3000	4000
3	10000	20000	30000	40000
4	100000	200000	300000	400000

In [101]:

print(type(df.iloc[0]))
df.iloc[0]

 

<class 'pandas.core.series.Series'>

Out[101]:

a    1
b    2
c    3
d    4
Name: 0, dtype: int64

In [102]:

print(type(df.iloc[[0]]))
df.iloc[[0]]

 

<class 'pandas.core.frame.DataFrame'>

Out[102]:

	a	b	c	d
0	1	2	3	4

In [103]:

print(type(df.iloc[1]))
df.iloc[1]

 

<class 'pandas.core.series.Series'>

Out[103]:

a    100
b    200
c    300
d    400
Name: 1, dtype: int64

In [104]:

print(type(df.iloc[[1]]))
df.iloc[[1]]

 

<class 'pandas.core.frame.DataFrame'>

Out[104]:

	a	b	c	d
1	100	200	300	400

In [105]:

print(type(df.iloc[[1,2,3]]))
df.iloc[[1,2,3]]

 

<class 'pandas.core.frame.DataFrame'>

Out[105]:

	a	b	c	d
1	100	200	300	400
2	1000	2000	3000	4000
3	10000	20000	30000	40000

In [106]:

print(type(df.iloc[1:3]))
df.iloc[1:4]

 

<class 'pandas.core.frame.DataFrame'>

Out[106]:

	a	b	c	d
1	100	200	300	400
2	1000	2000	3000	4000
3	10000	20000	30000	40000

In [ ]: