Given an array consisting of n
integers, find the contiguous subarray of given length k
that has the maximum average value. And you need to output the maximum average value.
Example 1:
Input: [1,12,-5,-6,50,3], k = 4 Output: 12.75 Explanation: Maximum average is (12-5-6+50)/4 = 51/4 = 12.75
Note:
- 1 <=
k
<=n
<= 30,000. - Elements of the given array will be in the range [-10,000, 10,000].
class Solution { public double findMaxAverage(int[] nums, int k) { int count = 0; int window = 0; for(int i = 0; i < nums.length; i++) { if(i < k) { count += nums[i]; window += nums[i]; } else { window = window - nums[i - k] + nums[i]; count = Math.max(count, window); } } return (double)count / k; } }