zoukankan      html  css  js  c++  java
  • 181. 超过经理收入的员工

    Employee 表包含所有员工,他们的经理也属于员工。每个员工都有一个 Id,此外还有一列对应员工的经理的 Id。

    +----+-------+--------+-----------+
    | Id | Name | Salary | ManagerId |
    +----+-------+--------+-----------+
    | 1 | Joe | 70000 | 3 |
    | 2 | Henry | 80000 | 4 |
    | 3 | Sam | 60000 | NULL |
    | 4 | Max | 90000 | NULL |
    +----+-------+--------+-----------+
    给定 Employee 表,编写一个 SQL 查询,该查询可以获取收入超过他们经理的员工的姓名。在上面的表格中,Joe 是唯一一个收入超过他的经理的员工。

    +----------+
    | Employee |
    +----------+
    | Joe |
    +----------+

    来源:力扣(LeetCode)

    # Write your MySQL query statement below
    select a.name as 'Employee'
    from 
        Employee as a,
        Employee as b
    where a.ManagerId=b.Id and a.Salary>b.Salary
  • 相关阅读:
    Next Permutation
    SpringMVC配置信息
    Servlet详解(转载)
    Length of Last Word
    Maximum Subarray**
    Divide Two Integers
    Generate Parentheses***
    http解码-2
    编码-1
    扫描工具对比
  • 原文地址:https://www.cnblogs.com/xxxsans/p/13701702.html
Copyright © 2011-2022 走看看