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  • [地图投影之C实现]BASIC_FU.C

    double Eccentricity()                             /*THE FIRST ECCENTRICITY*/
    {
       double a,b,c;
       a=pow(6378245.00,2);
       b=pow(6356863.00,2);
       c=(a-b)/a;
       c=sqrt(c);
       return c;
    }
    
    #define eccentricity Eccentricity()
    
    double Eccentricity1()                           /*THE SECOND ECCENTRICITY*/
    {
       double x,y;
       x=eccentricity*eccentricity;
       y=x/(1-x);
       return sqrt(y);
    }
    
    #define eccentricity1 Eccentricity1()
    
    double Meridian_radius(double latitude)
    {
       double x,y;
       x=sin(latitude);
       x=pow((1-eccentricity*eccentricity*x*x),1.5);
       y=major_radius*(1-eccentricity*eccentricity);
       return y/x;
    }
    
    double Prim_vertical_radius(double latitude)
    {
       double x;
       x=sin(latitude);
       x=pow(1-eccentricity*eccentricity*x*x,0.5);
       return major_radius/x;
    }
    
    double Parallel_radius(double latitude)
    {
       double x,y;
       x=cos(latitude);
       y=Prim_vertical_radius(latitude);
       return x*y;
    }
    
    double Meridian_length(double lowest_latitude,double highest_latitude)
    {
       double x,h,meridian_length=0;
       int n=10000;
       h=(highest_latitude-lowest_latitude)/n;
       for(x=lowest_latitude;x      meridian_length+=Meridian_radius(x)*h;
       return meridian_length;
    }
    
    double Parallel_length(double latitude,double lowest_longitude,double highest_longitude)
    {
       return Prim_vertical_radius(latitude)*cos(latitude)*(highest_longitude-lowest_longitude);
    }
    
    double Area(double lowest_latitude,double highest_latitude,double lowest_longitude,double highest_longitude)
    {
       double x=highest_longitude-lowest_longitude;
       double y=(highest_latitude+lowest_latitude)/2;
       double z=(highest_latitude-lowest_latitude)/2;
       double k=2*pow(major_radius,2)*(1-pow(eccentricity,2))*x;
       double a=1+pow(eccentricity,2)/2+3*pow(eccentricity,4)/8+5*pow(eccentricity,6)/16;
       double b=pow(eccentricity,2)/6+3*pow(eccentricity,4)/16+3*pow(eccentricity,6)/16;
       double c=3*pow(eccentricity,4)/80+pow(eccentricity,6)/16;
       double d=pow(eccentricity,6)/112;
       double area=0;
       area=k*(a*sin(z)*cos(y)-b*sin(3*z)*cos(3*y)+c*sin(5*z)*cos(5*y)-d*sin(7*z)*cos(7*y));
       return area;
    }
    
    double Radiam(double dms)                         /*CHANGE DGREE TO ARC*/
    {
       double p=3.14159265358979/180;
       return dms*p;
    }
    
    double U(double latitude)                  /*IMPORTANT CONST BEGIN FROM EX2*/
    {
       double a=Radiam(45),e=Eccentricity(),u;
       u=asin(e*sin(latitude));
       u=tan(a+latitude/2)/pow(tan(a+u/2),e);
       return u;
    }
    
    double U1(double latitude)            /*FOR GAMA IN MAIN OF EX4*/
    {
       double x;
       x=eccentricity1*eccentricity1*cos(latitude)*cos(latitude);
       return sqrt(x);
    }
    
    double Radiam1(double x,double y,double z)          /*CHANGE D.M.S. TO ARC*/
    {
       double m;
       m=x+y/60+z/3600;
       return Radiam(m);
    }


    e-mail:shisong.zhu@gmail.com
    GISer in China, for engineering
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  • 原文地址:https://www.cnblogs.com/columbus2/p/2867164.html
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