zoukankan      html  css  js  c++  java
  • Codeforces Round #134 (Div. 2)A. Mountain Scenery(简单)

    A. Mountain Scenery
    time limit per test
    2 seconds
    memory limit per test
    256 megabytes
    input
    standard input
    output
    standard output

    Little Bolek has found a picture with n mountain peaks painted on it. The n painted peaks are represented by a non-closed polyline, consisting of 2n segments. The segments go through 2n + 1points with coordinates (1, y1)(2, y2)...(2n + 1, y2n + 1), with the i-th segment connecting the point(i, yi) and the point (i + 1, yi + 1). For any even i (2 ≤ i ≤ 2n) the following condition holds: yi - 1 < yi andyi > yi + 1.

    We shall call a vertex of a polyline with an even x coordinate a mountain peak.

    The figure to the left shows the initial picture, the figure to the right shows what the picture looks like after Bolek's actions. The affected peaks are marked red, k = 2.

    Bolek fancied a little mischief. He chose exactly k mountain peaks, rubbed out the segments that went through those peaks and increased each peak's height by one (that is, he increased the y coordinate of the corresponding points). Then he painted the missing segments to get a new picture of mountain peaks. Let us denote the points through which the new polyline passes on Bolek's new picture as(1, r1)(2, r2)...(2n + 1, r2n + 1).

    Given Bolek's final picture, restore the initial one.

    Input

    The first line contains two space-separated integers n and k (1 ≤ k ≤ n ≤ 100). The next line contains2n + 1 space-separated integers r1, r2, ..., r2n + 1 (0 ≤ ri ≤ 100) — the y coordinates of the polyline vertices on Bolek's picture.

    It is guaranteed that we can obtain the given picture after performing the described actions on some picture of mountain peaks.

    Output

    Print 2n + 1 integers y1, y2, ..., y2n + 1 — the y coordinates of the vertices of the polyline on the initial picture. If there are multiple answers, output any one of them.

    Sample test(s)
    input
    3 2
    0 5 3 5 1 5 2
    
    output
    0 5 3 4 1 4 2 
    
    input
    1 1
    0 2 0
    
    output
    0 1 0 
    

    主要注意:following condition holds: yi - 1 < yi andyi > yi + 1.即可。答案不唯一。

    #include <iostream>
    using namespace std;
    
    int a[205];
    
    int main()
    {
        int n, k;
        while(cin >> n >>k)
        {
            for(int i = 0; i < 2 * n + 1; i++)
                cin >> a[i];
            for(int i = 1; k; i += 2)
                if(a[i] - 1 > a[i - 1] && a[i] - 1 > a[i + 1])
                {
                    a[i]--;
                    k--;
                }
            for(int i = 0; i < 2 * n; i++)
                cout << a[i] << " ";
            cout << a[2 * n] << endl;
        }
        return 0;
    }
    


  • 相关阅读:
    [北京省选集训2019]生成树计数
    阿里云轻量级服务器的日常操作
    阿里云轻量级服务器上搭建jdk、Tomcat、mysql、zookeeper步骤!!!
    mysql如何记录数据的创建时间和更新时间??
    解决ssm中文乱码问题,上传文件中文乱码的问题
    zookeeper的安装配置问题;
    zookeeper解决启动提示:找不到或者无法加载主类org. apache. zookeeper. server. guorum. QuorumPeerMlain的问题
    《数据采集与网络爬虫》之数据解析
    《数据采集与网络爬虫》环境篇
    《数据采集与网络爬虫》之抓取网页
  • 原文地址:https://www.cnblogs.com/cszlg/p/2910487.html
Copyright © 2011-2022 走看看