zoukankan      html  css  js  c++  java
  • lightoj--1043-- Triangle Partitioning (水题)

    Time Limit: 500MS   Memory Limit: 32768KB   64bit IO Format: %lld & %llu

    Submit Status

    Description

    See the picture below.

    You are given AB, AC and BC. DE is parallel to BC. You are also given the area ratio between ADE and BDEC. You have to find the value of AD.

    Input

    Input starts with an integer T (≤ 25), denoting the number of test cases.

    Each case begins with four real numbers denoting AB, AC, BC and the ratio of ADE and BDEC(ADE / BDEC). You can safely assume that the given triangle is a valid triangle with positive area.

    Output

    For each case of input you have to print the case number and AD. Errors less than 10-6 will be ignored.

    Sample Input

    4

    100 100 100 2

    10 12 14 1

    7 8 9 10

    8.134 9.098 7.123 5.10

    Sample Output

    Case 1: 81.6496580

    Case 2: 7.07106781

    Case 3: 6.6742381247

    Case 4: 7.437454786

    Source

    Problem Setter: Jane Alam Jan

    现在给出了AB,AC,BC以及三角形与梯形面积比值,求AD
    #include<stdio.h>
    #include<string.h>
    #include<math.h>
    int main()
    {
    	int t;
    	int K=1;
    	scanf("%d",&t);
    	while(t--)
    	{
    		double a,b,c,k;
    		scanf("%lf%lf%lf%lf",&a,&b,&c,&k);
    		double ad=a*sqrt(k/(1+k));
    		printf("Case %d: %.6lf
    ",K++,ad);
    	}
    	return 0;
    }


  • 相关阅读:
    HDU-4035 Maze
    poj 3744 Scout YYF I
    HDU 4911 Inversion
    HDU-3001 Travelling
    HDU 4539 郑厂长系列故事——排兵布阵
    poj 3311 Hie with the Pie
    poj-1185 炮兵阵地
    位运算
    HDU-1438 钥匙计数之一
    poj 3254 Corn Fields
  • 原文地址:https://www.cnblogs.com/playboy307/p/5273639.html
Copyright © 2011-2022 走看看