Find The Multiple（poj 1426）

Description

Given a positive integer n, write a program to find out a nonzero multiple m of n whose decimal representation contains only the digits 0 and 1. You may assume that n is not greater than 200 and there is a corresponding m containing no more than 100 decimal digits.

Input

The input file may contain multiple test cases. Each line contains a value of n (1 <= n <= 200). A line containing a zero terminates the input.

Output

For each value of n in the input print a line containing the corresponding value of m. The decimal representation of m must not contain more than 100 digits. If there are multiple solutions for a given value of n, any one of them is acceptable.

Sample Input

2
6
19
0

Sample Output

10
100100100100100100
111111111111111111

题意很明确；输入一个数，输出这个数的哟个整倍数，输出的数必须只有0和1组成；我会告诉你这题Special Judge?? 
题目不是很难，用 long long +bfs(其实无所谓用不用）266ms  水过；

#include<queue>
#include<cstdio>
using namespace std;
int N;
void bfs()
{
    long long i,q,p=1;
    queue<long long>que;
    que.push(p);
    while(!que.empty())//简单BFS
    {
        p=que.front();
        que.pop();
        for(i=0;i<2;i++)//因为只有 0和1
        {
            q=10*p+i;
            if(q%N==0)
            {
                printf("%lld
",q);
                return ;
            }
            que.push(q);
        }
    }
}
int main()
{
    int a,b;
    while(scanf("%d",&a)&&a)
    {
        if(a==1)//1有点特殊，所以单独处理；
        {
            printf("1
");
            continue;
        }
        N=a;
        bfs();
    }
    return 0;
}