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  • Educational Codeforces Round 65 (Rated for Div. 2)

    A. Telephone Number

    #include <bits/stdc++.h>
    using namespace std;
    
    int T, N;
    string s;
    
    int main() {
        scanf("%d", &T);
        while(T --) {
            bool flag = true;
            scanf("%d", &N);
            cin >> s;
            if(N < 11) flag = false;
            else if(N == 11) {
                if(s[0] == '8') flag = true;
                else flag = false;
            } else {
                int temp = -1;
                for(int i = 0; i < N; i ++) {
                    if(s[i] == '8') {
                        temp = i;
                        break;
                    }
                }
                if(temp == -1) flag = false;
                else if(N - temp - 1 >= 10) flag = true;
                else flag = false;
            }
    
            if(flag) printf("YES
    ");
            else printf("NO
    ");
    
        }
        return 0;
    }
    View Code

    B. Lost Numbers

    #include <bits/stdc++.h>
    using namespace std;
    
    int a[10] = {4, 8, 15, 16, 23, 42};
    int ans[10];
    
    int main() {
        for(int i = 1; i <= 4; i ++) {
            printf("? %d %d
    ", i, i + 1);
            fflush(stdout);
            scanf("%d", &ans[i]);
        }
    
        do {
            if(a[1] * a[0] == ans[1] && a[2] * a[1] == ans[2] && a[3] * a[2] == ans[3] && a[4] * a[3] == ans[4])
                break;
        } while(next_permutation(a, a + 6));
    
        printf("!");
        for(int i = 0; i < 6; i ++)
            printf(" %d", a[i]);
        printf("
    ");
    
        return 0;
    }
    View Code

    C. News Distribution

    #include <bits/stdc++.h>
    using namespace std;
    
    const int maxn = 5e5 + 10;
    int N, M;
    int f[maxn], cnt[maxn];
    
    void init() {
        for(int i = 1; i <= N; i ++)
            f[i] = i;
    }
    
    int Find(int x) {
        if(f[x] != x) f[x] = Find(f[x]);
        return f[x];
    }
    
    void Merge(int x, int y) {
        int fx = Find(x);
        int fy = Find(y);
        if(fx != fy) {
            f[fx] = fy;
        }
    }
    
    int main() {
        scanf("%d%d", &N, &M);
        init();
        while(M --) {
            int K;
            scanf("%d", &K);
            if(K) {
                for(int k = 0; k < K; k ++) {
                    int x;
                    int st;
                    scanf("%d", &x);
                    if(k == 0) st = x;
                    else Merge(st, x);
                }
            }
        }
    
        for(int i = 1; i <= N; i ++)
            cnt[Find(i)] ++;
    
        for(int i = 1; i <= N; i ++)
            printf("%d%s", cnt[Find(i)], i != N ? " " : "
    ");
    
        return 0;
    }
    View Code

    D. Bicolored RBS

    #include <bits/stdc++.h>
    using namespace std;
    
    const int maxn = 2e5 + 10;
    int N;
    int l[maxn];
    string s;
    
    int main() {
        scanf("%d", &N);
        cin >> s;
        l[0] = 1;
        for(int i = 1; i < N; i ++) {
             if(s[i] == '(') {
                    if(s[i - 1] == '(')
                        l[i] = l[i - 1] + 1;
                    else l[i] = l[i - 1];
                }
    
             else {
                if(s[i - 1] == ')') l[i] = l[i - 1] - 1;
                else l[i] = l[i - 1];
             }
        }
    
        for(int i = 0; i < N; i ++) {
            if(l[i] % 2) printf("0");
            else printf("1");
        }
    
        printf("
    ");
    
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/zlrrrr/p/11026769.html
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